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Find the tangent of the following curve, y=xe^x, at x=1 expressing it in the form y=mx+c?

Firstly, we calculate the y-value when x=1, namely y=e. Then we need to find the gradient of this curve at x=1, which can be determined by taking the derivative of y and then valuate it at x=1. So dy/dx=xe^x...
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Answered by Bruno S. • Maths tutor
18997 Views

given y=(1+x)^2, find dy/dx

There are two ways in which this we can do this, The first is explanding the brackets to get 1+2x+x 2 and differentiating to get 2+2x. The second way is using the chain rule , let u=1+x such that y=u 2 and d...
SG
Answered by Sam G. • Maths tutor
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What is the best way to solve simultaneous equations?

The easiest way to solve simultaneous equations is to label the equations so you clearly follow them throughout. For example, say you are asked to solve the unknowns for the simultaneous equations 3x-y=8 and...
LW
Answered by Lucy W. • Maths tutor
6176 Views

What is the product rule and when do you use it?

The product rule is used when finding the derivative of the product of two functions - two functions multipled together. If y = f(x)g(x), then dy/dx = f'(x)g(x) + f(x)g'(x) Where f'(x) is the derivative of f...
TJ
Answered by Tom J. • Maths tutor
5511 Views

How do I solve the quadratic equation x^2+4x+3=0

When solving a quadratic equation like this it is useful to write it in the form (x+a)(x+b)=0, as this is simply saying 'two numbers multiplied together equal zero'. A general rule in maths is that whenever ...
ER
Answered by Edward R. • Maths tutor
7051 Views