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Factorise and simplify (6x-42)/((x^2)-49)

When we factorise, we are trying to put a long expression into a couple of brackets to make it neater and easier to work with. It is the opposite to multiplying out brackets. To start off with, we will facto...
RS
Answered by Robert S. • Maths tutor
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If s=ut + 1/2 at^2 , a) make a the subject of the expression b) make u the subject of the expression c) if s=10, t=2 and u=4 find the value of a

a) s=ut + 1/2 at 2 Firstly , take the ut to the left hand side of the equation in order to isolate the 1/2 at 2 .s-ut=1/2 at 2 Then multiply both sides by 2 to leave just at 2 on the right hand side.2s-2ut=a...
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Answered by Freddy Y. • Maths tutor
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Given that F(x) = X^2 - 10X + 17. Write F(x) in the form of (x+a)^2 + b = 0, where a, & b are constants.

So we know that our equation is: X 2 - 10X +17 = 0. STEP 1: rearrange this equation to get x on one side: X 2 - 10X = -17. Lets call this, "equation 1". STEP 2: Understand that (X + a) 2 = X 2 + 2a...
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Answered by Rumit M. • Maths tutor
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Let p(x) = 30 x^3 -7 x^2 - 7 x + 2. Prove that (2x + 1) is a factor of p(x) and factorise p(x) completely.

Using the Factor Theorem , we know that (2x + 1) = 2(x + 1/2) = 2(x - (-1/2) ) is a factor of p(x) if and only if p(-1/2) = 0 , which is true. Now that we know a factor of p(x), we use the polynomial divisio...
Answered by • Maths tutor
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proof for the derivative of sin(x) is cos(x) (5 marks)

let f(x)=sin x f'(x) lim h-> 0 = ( sin(x+h) - sin(x))/h. f'(x) lim h-> 0 =( sin(x)cos(h) + cos(x)sin(h) - sin(x))/ h. f'(x) lim h-> 0=(sin(x)(cos(h)-1)/h + cos(x) (sin(h))/h. then as h tends to zero...
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Answered by Nicola P. • Maths tutor
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