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If a 5 metre ladder is resting against a wall and the bottom of the ladder is 3 metres away from the wall, and someone pulls the bottom of the ladder away at a speed of 1 metre per second, calculate the speed of the top of the ladder after t seconds

After t seconds the distance between the bottom of the ladder and the wall is t metres. Let x denote the distance that the top of the ladder has moved after t seconds. Now use the theorem of Pythagoras to ob...
OB
Answered by Oliver B. Maths tutor
3542 Views

Solve 5(x-6) < 20

When we solve this, it's going to be the same process as solving 5(x-6) = 20, except at each step we need to think about whether we change the inequality round or keep it the same. There are two ways of doin...
JS
Answered by Joseph S. Maths tutor
5406 Views

Given y = 2x(x2 – 1)5, show that (a) dy/dx = g(x)(x2 – 1)4 where g(x) is a function to be determined. (b) Hence find the set of values of x for which dy/dx > 0

Given y = 2 x ( x 2 – 1) 5 , show that (a) d y/dx = g( x )( x 2 – 1) 4 where g( x ) is a function to be determined. dy/dx= (2)( x 2 – 1) 5 + (2x)*5(x 2 – 1) 4 (2x) dy/dx= ( x 2 – 1) 4 ( 2( x 2 – 1) + 20x 2 )...
AI
Answered by Abi I. Maths tutor
10913 Views

√5(√8 + √18) can be written in the form a√10 where a is an integer. Find the value of a.

√40 + √90 = (√10 x √4 ) + (√10 x √9 ) = 2√10 + 3√10=5√10
AI
Answered by Abi I. Maths tutor
5392 Views

Solve 5(x + 3) < 60

5(x + 3) &lt; 60Multiple the number outside of the bracket with the contents of the bracket:5x + 15 &lt;60 Next, bring all the numbers to one side 5x &lt;60-15Now simplify 5x &lt; 45Simply further x &lt; 45/...
PJ
Answered by Priyancaa J. Maths tutor
4038 Views