Solve 5(x-6) < 20

When we solve this, it's going to be the same process as solving 5(x-6) = 20, except at each step we need to think about whether we change the inequality round or keep it the same. There are two ways of doing the first step, we could divide both sides by 5 or we could expand out the bracket on the left hand side. I think we should expand out, but it's really up to what you'd prefer to do. 5(x-6)= 5x-30, so our inequality becomes 5x-30 < 20. We can add 30 to both sides. Adding or subtracting doesn't change the direction of the inequality, so we get 5x<50. Now we would usually divide both sides by 5. Since 5 is positive, we don't change the direction of the inequality, we would do that if we multiplied or divided by a negative number, so we get x<10.

What would we have done if 5(6-x)<20?