Top answers

A mass of 3kg rests on a rough plane inclined at 60 degrees to the horizontal. The coefficient of friction is 1/5. Find the force P acting parallel to the plane applied to the mass, in order to just prevent motion down the plane.

Firstly draw a diagram of the problem.Then resolve the forces into their components parallel and perpendicular to the plane.Resolving parallel: P + Fmax = 3gsin(60) equation 1.Resolving perpendicular: R = 3g...
JM
Answered by Jonathan M. • Maths tutor
5114 Views

Consider the infinite geometric sequence 25 , 5 , 1 , 0.2 , ... (a) Find the common ratio. (b) Find (i) the 10th term; (ii) an expression for the nth term. (c) Find the sum of the infinite sequence.

QUESTION (a) R = U(n+1)/U(n ) = 5/25= 0.2(b) (i) U(10) = 25 x (1/5)^9 = 0.0000128 (ii) U(n) = 25 x (1/5)^(n-1)(c) S = U(1)/(1-r) = 25/(1-(1/5))=25/(4/5))=125/4=31.25
CR
Answered by Carlota R. • Maths tutor
6683 Views

Differentiate x^3⋅cos(5⋅x) with respect to x.

In order to solve this problem we will have to use the product rule as follows: d/dx[x^3⋅cos(5⋅x)]=[d/dx(x^3)]⋅cos(5 x)+(x^3)⋅[d/dx[cos(5 x)]]=(3⋅x^2)⋅cos(5⋅x)+(x^3)⋅−5⋅sin(5⋅x )=3⋅x^2⋅cos(5⋅x)−5⋅x^3⋅sin(5⋅x)
TL
Answered by Tianyu L. • Maths tutor
6626 Views

Work out 2 7/15 -1 2/3

First turn into improper fractions37/15 - 5/3Get same denominator on bottom37/15-25/15Take away numerator (37-25)/15= 12/15 Simplify 4/5
HG
Answered by Henry G. • Maths tutor
6049 Views

How would you factorise x^2 + 4x + 4

This is in the form ax 2 + bx + cWhere, a= 1b=4c=4To factor we have to find two numbers that:Add up to b , in this case 4 Multiply together to give c , in this case also 4 So we deduce that the two numbers a...
TB
Answered by Toby B. • Maths tutor
4697 Views