A mass of 3kg rests on a rough plane inclined at 60 degrees to the horizontal. The coefficient of friction is 1/5. Find the force P acting parallel to the plane applied to the mass, in order to just prevent motion down the plane.

Firstly draw a diagram of the problem.Then resolve the forces into their components parallel and perpendicular to the plane.Resolving parallel: P + Fmax = 3gsin(60) equation 1.Resolving perpendicular: R = 3gcos(60) =14.7N equation 2. Then substitute Fmax= Mu.R into equation 1 and then sub R (equation 2) into equation 1. Then solve to find P. P = 3gsin(60)- Mu.R P = 3gsin(60) - 0.2x14.7= 22.5 N

JM
Answered by Jonathan M. Maths tutor

4389 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do I find the roots of a quadratic equation?


1. A small stone is dropped from a height of 25 meters above the ground. i) Find the time taken for the stone to reach the ground ii) Find the speed of the stone as it reaches the ground


Integrate sinxcosx dx


What is the point of differentiation?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning