A mass of 3kg rests on a rough plane inclined at 60 degrees to the horizontal. The coefficient of friction is 1/5. Find the force P acting parallel to the plane applied to the mass, in order to just prevent motion down the plane.

Firstly draw a diagram of the problem.Then resolve the forces into their components parallel and perpendicular to the plane.Resolving parallel: P + Fmax = 3gsin(60) equation 1.Resolving perpendicular: R = 3gcos(60) =14.7N equation 2. Then substitute Fmax= Mu.R into equation 1 and then sub R (equation 2) into equation 1. Then solve to find P. P = 3gsin(60)- Mu.R P = 3gsin(60) - 0.2x14.7= 22.5 N

JM
Answered by Jonathan M. Maths tutor

4261 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Differentiate the function X^4 - (20/3)X^3 + 2X^2 + 7. Find the stationary points and classify.


What is 'completing the square' and how can I use it to find the minimum point of a quadratic curve?


b) The tangent to C at P meets the coordinate axes at the points Q and R. Show that the area of the triangle OQR, where O is the origin, is 9/(3-e)


Show that (sec(x))^2 /(sec(x)+1)(sec(x)-1) can be written as (cosec(x))^2.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences