Differentiate x^3⋅cos(5⋅x) with respect to x.

In order to solve this problem we will have to use the product rule as follows: d/dx[x^3⋅cos(5⋅x)]=[d/dx(x^3)]⋅cos(5x)+(x^3)⋅[d/dx[cos(5x)]]=(3⋅x^2)⋅cos(5⋅x)+(x^3)⋅−5⋅sin(5⋅x)=3⋅x^2⋅cos(5⋅x)−5⋅x^3⋅sin(5⋅x)

TL
Answered by Tianyu L. Maths tutor

5722 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

The point P (4, –1) lies on the curve C with equation y = f( x ), x > 0, and f '(x) =x/2 - 6/√x + 3. Find the equation of the tangent to C at the point P , giving your answer in the form y = mx + c. Find f(x)


The polynomial p(x) is given: p(x)=x^3+2x^2-5x-6, express p(x) as the product of three linear factors


Differentiate with respect to x: y=2^x


Three forces of magnitude 50N, PN, QN all act in a horizontal plane in equilibrium. The diagram shows the forces. DIAGRAM: QN = EAST, 50 = SOUTH, PN = 120 DEGREES ANTICLOCKWISE FROM QN a) Find P. b) Find Q.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences