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Find the integral of the following equation: y = cos^2(x)

First convert y into a suitably form.cos(2x) = 1 - 2cos 2 (x)cos 2 x = (1-cos(2x))/2 integral of y = integral of (1-cos(2x))/2 = (1/2)*(x-(1/2)sin(2x)) + C = x/2 - sin(2x)/4 + C
MH
Answered by Marc H. Maths tutor
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What is a geometric sequence?

A sequence is defined as a function with domain the set of the natural numbers, and codomain the set of the real numbers. A geometric sequence (a_n) is a sequence of the form: a_n = a_(n-1)*r, where r is a c...
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Answered by Georgios K. Maths tutor
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The equation of a curve is xy^2= x^2 +1. Find dx/dy in terms of x and y, and hence find the coordinates of the stationary points on the curve.

dy/dx = (2x-y 2 )/(2xy)Stationary points: (1, root(2)) , (1, -root (2))
RS
Answered by Rishi S. Maths tutor
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The function f has a local extreme at point (1,4). If f''(x)=3x^2+2x, then find f(0)?

A local extreme point would mean that f'(1)=0. Since integration is the inverse application of derivation, to obtain f'(x) function we integrate the f''(x) function. Bearing in mind the integration rule of i...
MT
Answered by Moris T. Maths tutor
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Solve the simultaneous equation: 2x + y = 18, x - y = 6

First, we simply label the two equations as 'Equation 1' and 'Equation 2' respectively. So we have: Equation 1: 2x + y = 18and Equation 2: x - y = 6. In simultaneous equations, there are two variables: x and...
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Answered by Harry M. Maths tutor
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