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A curve has equation y = 20x - x^2 - 2x^3 . The curve has a stationary point at the point M where x = −2. Find the x- coordinate of the other stationary point of the curve

A stationary point on a curve is when the differential of the equation of the curve = 0. In other words when dy/dx = 0Take the equation in the question: y = 20x - x 2 - 2x 3 A simple rule to find the differe...
HJ
Answered by Henry J. Maths tutor
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Let a = 4b + 5(c - b). Find the value of c when a = 8 and b = 7.

a = 4b + 5(c - b) - question8 = (4*7) + 5(c - 7) - insert values given in question8 = 28 + 5c -35 - multiply and expand brackets8 - 28 + 35 = 5c - take away 28 from the left and right-hand side of the equati...
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Answered by George H. Maths tutor
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Find the equation of the line through the following points: (-2, -3) and (1, 5)

Note the formula: y - y 1 = m(x - x 1 )x, y, x 1, y 1 refer to the values of your given coordinates. 'm' symbolises the gradient of the line you are asked to findRearrange the formula to make 'm' the subject...
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Answered by Tise O. Maths tutor
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Solve the equation 18x^2-3x=6

First put the equation into the correct form by setting it to 0:18x^2-3x-6=0Look for the common factor in the equation and take it out:3(6x^2-x-2)Using the grid method (which I would show on whiteboard) fact...
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Answered by Grace H. Maths tutor
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Expand and simplify (x-4)(2x+3y)^2

Firstly, expand out the (2x+3y)^2 as (2x+3y)(2x+3y).Multiplying each term in the first bracket with each term from the second bracket gives 4x^2+6xy+6xy+9y^2 which simplifies to 4x^2+12xy+9y^2 by adding the ...
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Answered by Annie-May W. Maths tutor
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