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Find the values of X and Y from the simultaneous equations: 1) 2x + 5y = 33 2) x + 3y = 19

2x + 5y = 33 2) x + 3y = 19 multiply equation 2 by a factor of 2 giving you 2x + 6y = 38 Your two equation are now: 1) 2x + 5y = 33 3) 2x + 6y = 38 Subtract 3 from 1 to eliminate the x's Giving you Y = 5 Now...
CC
Answered by Chris C. • Maths tutor
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∫6e^(2x+1) dx, find integral

6 ∫ e^(2x+1) dx 6 ∫ (1/2)(e^(2x+1))3e^(2x+1) + c
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Answered by Dila Y. • Maths tutor
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Simplify (􏰀36x^−2)􏰁^ 0.5

36/x^2 = (36)^0.5/(x^2)^0.56/x = 1/6x
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Answered by Dila Y. • Maths tutor
8046 Views

(i) Find the coordinates of the stationary point on the curve y = 3x^2 − 6/x − 2. [5] (ii) Determine whether the stationary point is a maximum point or a minimum point.

i) dy/dx = 0dy/dx = 6x + 6/x^2 6x + 6/x^2 = 06x^3 + 6 = 0x^3 + 1 = 0x^3 = -1x = -1y = 7(-1, 7)ii) d^2y/dx^2 = 6 - 12/x^3 x = -1 6-12/(-1)^3 = 18>0 therefore, minimum point
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Answered by Dila Y. • Maths tutor
9169 Views

Find the Binomial Expansion of (1-5x)^4.

First I would set up how i was taught using Pascals Triange. As this is to the power of 4 the numbers across will be 1 4 6 4 1.Then I would multiply each number by the correct power of either (-5x) or (1). A...
MV
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