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Write 144 as a product of its prime factors

To do this, we draw a prime factor tree (whiteboard). The easiest way is to keep dividing by 2 (which is a prime number) until we get an odd number. 144/2 = 72 and 72/2 = 36 and 36/2 = 18 and 18/2 = 9 which ...
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Answered by Ewan S. Maths tutor
30018 Views

Solve x2 + 2x − 4 = 0 leave in simplest form.

This is a Quadratic equation so you would try to factorise.If it was on the calculator paper use the equation (You don't need to memories this equation, but you have to be commutable using it).However this i...
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Answered by Malee N. Maths tutor
5281 Views

2x + y = 10 and 4y - 5x = 1, solve for x and y.

Rearrange one of the linear equations in order to have x or y written as an equation of the other. I.E 1) y =10 - 2x.Then substitute this value into the other equation: 4(10 - 2x) - 5x = 1, hence 39 = 13x wh...
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Answered by Nathan T. Maths tutor
4880 Views

Solve the equation 3^(2x+1)=1000

We can use logarithms with base 3 to solve this equation.2x+1=log 3 10002x=log 3 (1000)-1x=0.5(log 3 (1000)-1)x=2.64
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Answered by Samuel D. Maths tutor
5545 Views

Integrate 6/(e^x+2) between 1 and 0

By Trapezium Rule (with 5 segments)x 0 0.2 0.4 0.6 0.8 1y 2 1.8625 1.71830 1.56981 1.41994 1.27165≈1⁄2*(0.2) [2+1.27165+ 2( 1.8625 + 1.71830 + 1.56981 + 1.41994)]≈1⁄10 *16.41283 = 1.641By Substitution/ Parti...
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Answered by Christopher H. Maths tutor
4874 Views