Top answers

Find the equation of the straight line passing through the points (7,5) and (8, 2)

To find the equation of a straight line we need two things, the gradient of the line and a point lying on the line. To find the gradient of this line we use the gradient formula: m = (y 2 -y 1 )/(x 2 -x 1 ) ...
RS
Answered by Rory S. • Maths tutor
7278 Views

Solve the equation: x^2 - 9x + 20 = 0

This is a quadratic equation, and is likely that x can satisfy either of two values. We know these must multiply to form 20 and summate to -9, and thus they are (x-4) and (x-5). Hence, x is either 4 or 5.
PM
Answered by Pippa M. • Maths tutor
8534 Views

Expand and Simplify: 16=(x-3)(x+3)

16 = (x-3)(x+3) --> 16 = x^2+3x-3x-9 --> 16 = x^2-9 --> x^2=25 --> x = +5 or -5
TT
Answered by Thaarabi T. • Maths tutor
4595 Views

Prove algebraically that (4n + 1)² − (2n − 1) is an even number for all positive integer values of n.

First of all expand the brackets and simplify the expression given:(4n+1)(4n+1)-(2n-1)= 8n 2 +8n+1-2n+1= 8n 2 +6n+2= 2(4n 2 +3n+1). Since the expression can be factorised with 2, and since 4n 2 +3n+1 will al...
SM
Answered by Shiv M. • Maths tutor
11478 Views

If a particle of mass m is launched vertically upwards from the ground with velocity u m/s, how long will it take to return to the ground in terms of m, u and g?

Taking upwards to be positive, and using the 'suvat' equation s=ut+1/2at 2 we know that u=u, a=-g and s=0 when the particle returns to the ground. Then we solve for t: 0=ut-1/2gt 2 0=t(u-1/2gt) So the partic...
JV
Answered by Jackie V. • Maths tutor
3612 Views