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Let y = 4t/(t^2 + 5). Find dy/dt, writing your answer in it's simplest form, and find all values of t for which dy/dt = 0
We use the quotient rule to find dy/dt. Let u = 4t and v = (t^2 + 5). Then, u' = 4 and v' = 2t. Hence,
dy/dt = u'v - v'u / v2 = 4(t^2 + 5) - 4t x 2t / (t^2 + 5)2 = 20 - 4t
