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In this question, take 'log' to mean 'log base 5'. Solve the equation log(x^2-5)-log(x) = 2*log(2)

Note that you can not take a positive base log of a negative number.  log5(x2-5) - log5(x) = 2log5(2) => log5((x2-5)/x) = log5

ML
Answered by Milan L. Maths tutor
3297 Views

What is the difference between 'J'aimerais de nouvelles chaussures' and 'Jaimerais les nouvelles chaussures' ?

Articles always seem tricky in French, but with practice they are simple! In the first example the indefinite article 'des' is used - this means that the sentence is talking about new shoes in general. In...

SL
Answered by Shereen L. French tutor
2776 Views

Solve the

5

ML
Answered by Milan L. Maths tutor
3391 Views

Find dy/dx such that y=(e^x)(3x+1)^2.

We will solve this question with the knowledge that dy/dx = u.(dv/dx) + v.(du/dx), where y=u.v We have y=e^x(3x+1)^2. First, we want to find u & v. By splitting the function, we have that u=e^x and v=...

SB
Answered by Stefanie B. Maths tutor
4264 Views

Show that 2tan(th) / (1+tan^2(th)) = sin(2th), where th = theta

We have 2tan(th) / (1 + tan^2(th)) = sin(2th)

We know that tan(A) = sin(A) / cos(A), and 1 + tan^2(A) = sec^2(A)

Therefore => (2sin(th) / cos(th)) / sec^2(th)

=> 2sin(th)*cos^2(...

IC
Answered by Ian C. Maths tutor
3696 Views

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