Top answers

All subjects
All levels

In a titration, 50 cm3 of sodium hydroxide with a concentration of 0.3 mol/dm3 was neutralised by 60 cm3 of hydrochloric acid. Calculate the concentration of the hydrochloric acid in mol/dm3.

HCl + NaOH = NaCl + H2O. Moles = volume (dm3) x concentration (mol/dm3). Moles of NaOH: volume x concentration = (50/1000) x 0.3 = 0.015 moles. 1 to 1 ratio of HCl to NaOH, so there were 0.015 moles of HC...

AV
Answered by Aarushi V. Chemistry tutor
25073 Views

Simplify 3x^(2)+13x-30/x^(2)-32

First of all spot that the bottom of the fraction is a result of the difference of two squares and can be rearranged to (x+6)(x-6), making the fraction equal to 3x^(2)+13x-30/(x+6)(x-6). Use this knowledg...

NP
Answered by Nicolaas P. Maths tutor
4054 Views

find dy/dx of the equation y=ln(x)2x^2

Here it is necessary to use the chain rule to solve the derivative. If we equate our equation in terms of the following notation: ln(x)='u'and 2x^2='v' and use the chain rule formula dy/dx=udv/dx+vdu/dx w...

PG
Answered by Pierce G. Maths tutor
3768 Views

Solve (4-2x)/(x+1)=x

To solve this equation, we need to collect all of the x^2 terms and the x terms together. To do this we should start by getting rid of the fraction on the left-hand side by multiplying both sides by the d...

EK
Answered by Emily K. Maths tutor
9045 Views

How do I keep a good line of argument throughout my essay?

Hello, thank you for the question. Concerning maintaining a good strong argument throughout your essay, it's always good to keep using the question throughout. For example, starting your paragraphs (main ...

ER
5072 Views

We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences