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The gradient of a curve is given by dy/dx = 6sqrt(x) + 2. The curve passes through the point (16, 38). Find the equation of the curve.

dy/dx = 6x1/2 + 2 y = (62/3)x3/2 + 2x + c = 4x3/2 + 2x + c 38 = (4163/2) + (2*16) + c c = 38 - 256 - 32 = -250 y = 4x3/2 + 2x - 250

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Answered by Fraser W. Maths tutor
4495 Views

How do you integrate (x/(x+1)) dx without using substitution.

A tricky question which is actually really simple if you know the technique and will save a lot of time during the exam. The method is to simply add 1 and minus one to the numerator. so the integral becom...

Answered by Maths tutor
2975 Views

Differentiate 3x^(3) + 7x^(2) -4x

Using the formula for differentiation: if y=axN then dy/dx= Na*xN-1 apply this to each term in the equation given; first term: dy/dx= 9x2second term: dy/dx= 14xth...

MW
Answered by Michelle W. Maths tutor
3136 Views

How do I choose a question in the exam?

First of all you need to break down the wording of each question and find key words (e.g. in a question asking to discuss the 'unsayable' this is the key word that needs to be addressed) and pick out the ...

Answered by English tutor
1719 Views

Express (3-5x)/(x+3)^2 in the form A/(x+3) + B/(x+3)^2

A needs to be multiplied up by x+3 to make the fraction have the same in denominator as the other expressions. Then you need to equate the numerators. 3 - 5x = A(x+3) + B
You can gain two simultaneou...

Answered by Maths tutor
2603 Views

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