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Solve the simultaneous equations: (1) x^2 + y^2 = 25 and (2) y - 3x = 13

Sub (2) y = 13 + 3x into (1)x^2 + (13 + 3x)^2 = 25x^2 + 169 + 39x + 39x + 9x^2 = 2510x^2 + 78x + 144 = 05x^2 + 39x + 72 = 0 (/2)572 = 360 - need ab=360 such that a+b=39a = 24 b = 155x^2 + 24x + 1...

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Answered by Meghna M. Maths tutor
2793 Views

differentiate 3x^56

=(3x56)x55

MG
Answered by Madalina G. Maths tutor
3623 Views

Square ABCD has length (x+3)cm and area 10cm^2. Show x^2 + 6x = 1

First sketch square ABCD. Split length into 3cm and then xcm for side AB and the same for side AD. Split the area of this square into 4 segments (a, b, c and d) such that a is a 3cm by 3cm square, b and c...

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Answered by Meghna M. Maths tutor
4292 Views

The curve with the equation: y=x^2 - 32sqrt(x) + 20 has a stationary point P. Find the coordinates of P.

A stationary point implies that the gradient at this point will be equal to 0, it is a turning point in the graph. So we need to find the value of X at which dy/dx = 0. [where dy/dx is the gradient.]So we...

MB
Answered by Maninder B. Maths tutor
9501 Views

How do I memorise quotes?

The best way I have found through trial and error is to first create flashcards of those quotes. This lets you break down the many quotes you may need to remember into more manageable pieces of informatio...

EH
3508 Views

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