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How do I find the co-ordinates of a stationary point of a given line and determine whether it is a minimum or a maximum point?

When you find the first derivative of the equation and equate it to 0 then solve for x, you will find the x-coordinates of the stationary point(s) of the graph. For example, let's say f(x)=-x³+...

Answered by • Maths tutor

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Work out 2^14 ÷ (2^9)^2 in its simplest form

2¹⁴ ÷ (2⁹)²I would start with the second part of this equation as that looks like it needs simplifying. When 'powers of' are in brackets to each other, they are multipled ...

Answered by Sion D. • Maths tutor

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How do you find the first order derivative of sin(x) and cos(x) functions?

The general rules are:d(sin x)/ dx = cos xd(cos x)/ dx = -sinxHowever, if you have a constant k in the function such as y = sin(kx), the derivative will be dy/dx = kcos(kx). (For y = cos(kx), the derivati...

Answered by Niusha S. • Maths tutor

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Find the x-coordinates of any stationary points of the equation y = x^3 - 2x + 4/x

y = x^3 - 2x +4/x, dy/dx = 3x^2 - 2 - 4/(x^2) = 0 at the stationary points, 3x^4 - 2x^2 - 4 = 0, substitute in u for x^2: 3u^2 - 2u - 4 = 0, use the quadratic formula: u = (-(-2) +- sqrt((-2)^2 - 4

Answered by • Maths tutor

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60 students were taking a Maths, Physics or Chemistry exam. 38 of the students were male. 11 of the 32 students who were taking the Maths exam were female. 8 males were taking the Physics exam. 12 students were taking the Chemistry exam. One of the fe

60-38 = 22 females 32+12=44 students taking the Chemistry and Maths exam. Therefore 60-44=16 students were doing the Physics exam, so 16-8= 8 females were taking the Physics exam. This means that 22-11-8 ...

Answered by Harry B. • Maths tutor

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