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Integrate 3t^2 + 7t with respect to t, between 1 and three.

To integrate you add one to the power and divide by the new power, so this becomes:3t 3 /3 + 7t 2 /2 simplifying to t 3 + 7/2 t 2 If we were just performing indefinite integration you would need to remember ...
JM
Answered by Josh M. • Maths tutor
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ii) The maximum permitted sulfate concentration in water is 250mg dm^-3, 200cm^3 of aqueous BaCl2 is added to 300cm^3 of water at the maximum permitted sulfate level, and a white precipitate formed. Calculate the minimum conc. (mol dm^3)of the BaCl2

250x10^-3= 0.25g dm -3 sulfate mr x moles = mass0.25 x 3/10 = 0.075 g sulfatemr sulfare = 32 + (4 x 16) = 96moles sulfate = 0.075/96 = 7.8125 x10 -4 Per equation above: moles SO 4 2- = moles Ba 2+ Concentrat...
JM
Answered by Josh M. • Chemistry tutor
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What is the deadweight loss of a tax and how do I calculate it?

We have inverse aggregate supply and demand curve and our product is sold at the market equilibrium price. We know that a demand curve is downward sloping, that means there will be less goods demanded at a h...
JA
Answered by Jona A. • Economics tutor
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When aqueous barium chloride is added to a solution containing sulfate ions a white precipitate is formed. i)Write the ionic equation for the formation of this precipitate.

Ba 2+ (aq) +SO 4 2- (aq) ---->BaSO 4(s)
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Answered by Josh M. • Chemistry tutor
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Integrate (lnx)/x^2 dx between limits 1 and 5

Let I = integral[(lnx)/x^2 dx] for simplicity.Firstly, we realise we must use integration by parts. This is:Integral [u(x)v'(x) dx] = u(x)v(x) - Integral[u'(x)v(x) dx]So we can see that, by letting u(x)=lnx ...
JL
Answered by Jimmy L. • Maths tutor
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