Solve the simultaneous equations: y=x^2+4x-2, y=x+2

Equations: 1). y=x^2+4x-2 2.)y=x+2 x+2=x^2+4x-2 First put equation 1 in equation 2 0=x^2+3x-4 Make one side of the equation equal to 0 0=(x+4)(x-1) Factorise the equations Equations 3).x+4=0 4). x-1=0 One or both of the brackets in the factorised form must equal 0 for the whole equation to be equal to 0. x=-4 x=1 Solve equations 3 and 4 Remember to find y by substituting in values of x into equation 2.) to fully solve the equations y=x+2 y=-2 y=3 Answer: When x=-4 y=-2, when x=1 y=3