x^2 - 10x + 21 = 0

  • First, factorise the quadratic equation.
  • Find two numbers that multiply to give 21 and add to give 10. 7 and 3
  • (x-7)(x-3)=0
  • Now find the value x so that when these brackets are multiplied together the answer is 0.
  • So either x=7 or x=3
  • You can check the answer by substituting 7 and 3 into the equation.
BS
Answered by Ben S. Maths tutor

4309 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the equation x^3-5x^2+7x-3=0


Whats the inverse of y = 2x+1/x-1 ?


What is the mean of the numbers: 1, 7, 25, 9 and 34?


Prove that the square of an odd number is always 1 more than a multiple of 4


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning