x^2 - 10x + 21 = 0

  • First, factorise the quadratic equation.
  • Find two numbers that multiply to give 21 and add to give 10. 7 and 3
  • (x-7)(x-3)=0
  • Now find the value x so that when these brackets are multiplied together the answer is 0.
  • So either x=7 or x=3
  • You can check the answer by substituting 7 and 3 into the equation.
BS
Answered by Ben S. Maths tutor

4774 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Find the equation of a straight line given two of its points (1,3) and (-2,5). Write your answer in the form y = mx + c.


Factorise the following quadratic, find the stationary point and y intersection: x^2-6x+9


work out: ( 4 × 10^3 )^2 + 3.5 × 10^7 and give your answer in standard form.


Find the interval for which x^2 - 7x + 10 </= 0


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning