How do I do this question: A small stone is projected vertically upwards from the point A with speed 11.2 m/s. Find the maximum height above A reached by the stone.
[Draw Diagram] We are given the inital velocity u=11.2m/s and we know the acceleration due to gravity is 9.8m/s^2. We need to find the distance 's'. When the stone is at its highest point the velocity will be v=0m/s. Using the equation v^2=u^2+2as we get 0=11.2^2-29.8s (make sure to get the minus sign for gravity) This comes to s=6.4m (show working on board)
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