How do I do this question: A small stone is projected vertically upwards from the point A with speed 11.2 m/s. Find the maximum height above A reached by the stone.

[Draw Diagram] We are given the inital velocity u=11.2m/s and we know the acceleration due to gravity is 9.8m/s^2. We need to find the distance 's'. When the stone is at its highest point the velocity will be v=0m/s. Using the equation v^2=u^2+2as we get 0=11.2^2-29.8s (make sure to get the minus sign for gravity) This comes to s=6.4m (show working on board)

LW
Answered by Luke W. Maths tutor

5429 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the derivative for y=5x^3-2x^2+7x-15


When I integrate by parts how do I know which part of the equation is u and v'?


Find the equation of the tangent to the circle (x-3)^2 + (y-4)^2 = 13 that passes through the point (1,7)


Explain the Principle of Moments.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences