Find the integral of xe^(-2x) between the limits of 0 and 1 with respect to x.

We can identify xe^(-2x) as a product and hence we will most probably need to use integration by parts.

We then set u = x and v' = x^(-2x). It is important to do it this way round so that when we differentiate u we are left with u' = 1 which is what will make the second integral easier to solve.

Substitute these values into the formula for integration by parts being sure to be careful to avoid any sign errors. Finally substitute in the limits and you should get the answer of 0.25 - 0.75e^(-2)

Answered by Tom B. Maths tutor

5108 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

What is the sum of the geometric series 1 + 1/3 + 1/9 + 1/27 ...


What is the angle between the position vectors a and b, where a = (6i - j + 3k) and b = (-4i + 2j + 10k)?


When you are working out dy/dx = 0, why do you do this and what does it mean?


Use simultaneous equations to find the points where the following lines cross: 3x - y = 4 and x^2 + 7y = 5


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy