Find the coordinates of the minimum point of the curve y=x^2+6x+5.

To answer this question is equivalent to minimising y=(x+3)^2-4. We have that all square numbers are greater than or equal to 0 so to minimise this equation, we require that (x+3)^2=0. This is satisfied only when x=-3. Then y=[(-3)+3]^2-4=-4. Our minimum point is therefore (-3,-4).

JI

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