The curve C is defined by x^3 – (4x^2 )y = 2y^3 – 3x – 2. Find the value of dy/dx at the point (3, 1).

When we find dy/dx we find the gradient of the curve at (3,1). Start by differentiating the left hand side (LHS) like so.. (whiteboard). Remember every time we differentiate a y value we multiply by dy/dx. This is because we differentiate y with respect to y and then multiply by dy/dx to get y differentiated with respect to x (by the chain rule). We now differentiate the RHS... (whiteboard) Now collect the dy/dx terms on the LHS and the other terms on the RHS like so... (whiteboard) Now sub in x=3 and y=1 and we obtain dy/dx=1/7.

CR
Answered by Caitlin R. Maths tutor

5274 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Given that y=(4x-3)^3 x sin2x find dy/dx


How do you find the gradient of a line at a certain point when f(x) is in the form of a fraction, where both the numerator and denominator are functions of x?


(5 + 2(2^0.5))(7 - 3(2^0.5))


How does the product rule for differentiation work


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning