Why does d/dx (tan(x)) = sec^2(x)?

This result comes from using a trig identity and the quotient rule. First, we write tan(x) as sin(x)/cos(x). Then we apply the quotient rule. After doing the standard derivatives, the numerator of our fraction becomes another trig identity, sine squared + cosine squared, which equals one. Now, looking at our fraction, we can see we have 1/cos^2(x). We can then rewrite this as (1/cos(x))^2. We apply our final trig identity now, 1/cos(x)=sec(x), and we see that d/dx tan(x) = sec^2(x). (Due to the nature of writing mathematics, this is far easier to represent and explain using the whiteboard)

TD
Answered by Tutor42661 D. Maths tutor

9717 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

The curve C has equation 4x^2 – y^3 – 4xy + 2^y = 0 The point P with coordinates (–2, 4) lies on C . Find the exact value of dy/dx at the point P .


Find the antiderivative of the function f(x)=(6^x)+1


Express: (x^2 + 5x - 14) / (2x^2 - 4x) as a fraction in it's simplest form.


Differentiate y^3 + 3y^2 + 5


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences