Find the set of values for x for which x^2 - 9x <= 36

Rearrange to get x^2 - 9x - 36 <= 0 Solve quadratic (x-12)(x+3) <= 0 Solve for x x = 12, x = -3

Now, we have key points 12 and -3, we need the range of values for x where x^2 - 9x - 36 <= 0.

So, we can visualise quadratic. It's positive, so the range of values lower than y=0 will be -3 < x < 12. This is the answer.

DD
Answered by Daniel D. Maths tutor

10245 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Given the equation 3x^2 + 4xy - y^2 + 12 = 0. Solve for dy/dx in terms of x and y.


Calculate the derivative of x^x


Solve 8(4^x ) – 9(2^x ) + 1 = 0


Define the derivative of a function f(x) and use this to calculate the derivative of f(x)=x^n for positive integer n.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning