How do you solve a simultaneous equation?

Take 2 equations say equation 1: 2y+4x=26 and equation 2: y+3x= 18. What we need to do is make either the two x values or the 2 y values be equal so that we can subtract one of the equations from the other. for example: In this case we would multiply the 2nd equation by 2, so that we get 2y in both equations. This gives us equation 1: 2y+4x=26 and the adjusted equation 2: 2y+6x=36. What we do now is subtract equation 2 from equation one which gives us -2x=-10, we then make them both positive and divide 10 by 2 to obtain x which gives us x=5. We then plug x=5 into equation 1 or 2 to find the value of y. In this case 2y+4*5=26 results in y= 3. Finally we can check that we have the right values for x and y by substituting both values of x and y that we found into the equation 2 and checking we get the right result.

BS
Answered by Bryony S. Maths tutor

3301 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Q = P / (R (4-t)), P=36, R= 3, t=-2


A car costs £300. The price is then reduced by 20%. However, the shop increases the new price by 15%. Fadhila says, "20 - 15 = 5, so the original price of the car has been reduced 5%". Is she right? What is the final price of the car?


Pythagoras: If you have a right angled triangle PQR, and length PQ=5cm, length QR=8cm (which is the longest length), then calculate length PR to two decimal places.


Solve the simultaneous equations 2x - 3y = 7 and 3x + 4y = 2. Do not use trail and improvement.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences