The point A lies on the curve y=5(x^2)+9x , The tangent to the curve at A is parralel to the line 2y-x=3. Find an equation to this tangent at A.
y-(any value of the function)=0.5(x-(any value in the domain))
e.g. Point with point A being (1,14) The answer would be y-14=0.5(x-1)
RA
Related Maths A Level answers
All answers ▸i) It is given that f(x)=(-5-33x)/((1+x)(1+5x)), express f(x) in the form A/(1+x) + B/(1+5x) where A,B are integers. ii) hence express the integral of f(x) between x=3 and x=0 in the form (p/q)ln4 where p,q are integers.
How do I calculate the reactant forces for the supports of the beam where the centre of mass is not same distance from each support?
Let R denote the region bounded by the curve y=x^3 and the lines x=0 and x=4. Find the volume generated when R is rotated 360 degrees about the x axis.
Integral of e^x*sinx