Solve the simultaneous equations: y=x/2 + 2 and 2y+3x=12
Label the equations (1): y=x/2 + 2 and (2): 2y+3x=12. Firstly, multiply equation (1)by 2, this will give you (1a): 2y=x+4, then, substitute (1a) into (2). This gives you (x+4)+3x=12. Therefore, 4x+4=12. 4x=12-4, 4x=8, giving the answer x=2. Substitute this in to equation (1) to solve for y. y=(2)/2 + 2, giving y=3.
JB
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