Differentiate y=4x^2+3x+9

Use the rule of "bringing down the power" and then reducing the power by 1. Start with 4x^2. "Bring down" the 2 to make (4)(2)x^2, then reduce the power by 1 to make 8x. Now repeat this with 3x (you can imagine this as 3x^1 if this is easier). Bring down the 1 to make (3)(1)x^1 and then reduce the power by 1 to make 3x^0 which is 3. 9 cannot be differentiated , so we just get 0. Overall, this gives us dy/dx = 8x + 3

TR
Answered by Tarryn R. Maths tutor

5602 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How would you expand (x+5y)^5?


What is the equation of a curve with gradient 4x^3 -7x + 3/2 which passes through the point (2,9)?


2x + y = 12. P = xy^2. Show that P = 4x^3 - 48x^2 + 144x


Curve C has equation 4x^2- y^3 - 4xy +2^y = 0 , point P (-2, 4) lies on C, find dy/dx at the point P


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences