Differentiate y=4x^2+3x+9

Use the rule of "bringing down the power" and then reducing the power by 1. Start with 4x^2. "Bring down" the 2 to make (4)(2)x^2, then reduce the power by 1 to make 8x. Now repeat this with 3x (you can imagine this as 3x^1 if this is easier). Bring down the 1 to make (3)(1)x^1 and then reduce the power by 1 to make 3x^0 which is 3. 9 cannot be differentiated , so we just get 0. Overall, this gives us dy/dx = 8x + 3

TR
Answered by Tarryn R. Maths tutor

5534 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How would I find a the tangent of a point on a line?


What is the derivative?


Earth is being added to a pile so that, when the height of the pile is h metres, its volume is V cubic metres, where V = (h6 + 16) 1 2 − 4.Find the value of dV/dh when h = 2.


Find the intergal of 2x^5 -1/(4x^3) -5 giving each term in its simplest form.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences