John ran a 450m race (2sf) in a time of 62 seconds (nearest second). Calculate the difference between his maximum and minimum average speed. (3sf)
S=D/T Max= 455(upper bound)/61.5(lower bound)= 910/123 m/s Min= 445(lower bound)/62.5 (upper bound) = 178/25 m/s Max - Min= 856/3075 m/s
CR
Related Maths GCSE answers
All answers ▸Solve the simultaneous equations: 2x-3y = 16 x+2y= -6
How do you solve simultaneous equations
There are 5 blue counters and 5 red. x takes 2 counters out of the bag without replacing them. What is the probability x took 2 red counters.
A cylinder has radius 2cm and height 9cm. A cone has radius r cm and height h cm. The ratio r : h is 1 : 4. The volume of the cone is equal to the volume of the cylinder. Work out the value of r.