Solve the simultaneous equations: 3x+2y=4 and 2x+y=3

When solving simultaneous equations there are several options, the two most common methods being substitution and elimination. For this example I shall use elimination. In order to do so, either x or y must have the same coefficient in both equations. The simplest way of doing so is to multiply the second equation by 2 in order that the coefficient of y in both equations is 2. This gives us 4x+2y=6. We can then subtract the second equation from the first to eliminate y as a variable. This leaves -x=-2 or more simply put, x=2. We then substitute x=2 into either equation to solve for y. If we use the first we get: 3(2)+2y=4 or 6+2y=4. To simplify this, we take 6 over to the right side and subtract it from 4 (since signs become the opposite when taken over the equals sign). We are left with: 2y=-2. We divide both sides by 2 and are left with y=-1.

Answered by Catherine G. Maths tutor

10143 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve x^2+6x+5=0


Expand and simplify (3x + 2)(4x - 3).


Solve the simultaneous equations. 2x + y = 18 x - y = 6


A rectangle has an area of 20 cm2. Its lengths are enlarged by a factor of 3. What is the area of the new rectangle?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy