Answers>Maths>IB>Article

A scalene triangle has base of 5cm. The angle opposite to the base is 63°, and a second angle is 72°. Find the area of the traingle

Using the sine rule it's possible to find the length opposite to the 72° angle. Therefore: 5/(sin63)=x/(sin72) x=5sin(72)/sin(63)=5.34 At this point, the third angle is needed. Since a triangle has a total sum of the angles of 180°, the following calculation is done: alpha=180-(63+72)=45° The formula for the area of a triangle is: Area=0.5absinC The two sides known are 5 and 5.34, and therefore the angle that is needed is subsequently the last one that was calculated, i.e.: 45° Adding these numbers in will yield the final result: Area=0.5x5x5.34xsin(45)=9.35cm^2

AL
Answered by Alessandro L. Maths tutor

2241 Views

See similar Maths IB tutors

Related Maths IB answers

All answers ▸

The function f has a local extreme at point (1,4). If f''(x)=3x^2+2x, then find f(0)?


Let f(x)= x^2+4, and g(x)= 3x; Find g(f(1))


The normal to the curve x*(e^-y) + e^y = 1 + x, at the point (c,lnc), has a y-intercept c^2 + 1. Determine the value of c.


What is a geometric sequence?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences