How to differentiate a function?

Let's look at the function y = 3x^2 + 6x + 3. Differentiating it gives us the derivative of y: dy/dx = 6x + 6. The original function has three terms. Let's look at each term:

  1. 3x^2 (^2 means to the power of 2). This becomes 6x, because we take the index 2, multiply it by the coefficient 3, and subtract 1 from the index.
  2. 6x becomes 6, because we again multiply the index by the coefficient and subtract one from the index. This gives us 6x^0, but anything to the power of 0 equals 1, so we are left with just 6.
  3. 3 is removed altogether, because it doesn't have an x attached to it.
ES

Related Maths GCSE answers

All answers ▸

1a) Simplify 2a^3 x a^5 1b) (4x^2)^3 1c) 2(3y+1) - 3(y-4)


I don't understand how to expand and simplify brackets such as (x-3)(x+5)


Adam is going to get a loan of £ 720 to help pay for the holiday. Adam will have to pay back the £ 720 plus interest of 15 %. He will pay this back in 12 equal monthly installments. How much money will Adam pay back each month?


Solve this simultaneous equations, clearly showing all of your workings: x^2 + 2y =9, y - x = 3