Tim stretches by leaning against a pole that is 1.5 metres tall and at a right angle to the floor. Tim is standing 0.5 metres away from the pole, how tall is Tim; leaving your answer in terms of metres? (2.d.p)

This can be solved using Pythagoras. We know that the pole is 90 degrees to the floor so the height of the pole is the opposite side. The distance between Tim and the pole is therefore the adjacent and hence we can find the hypotenuse. Using the formula sqrt(a^2+b^2)=c^2 we can substitute in for a=1500cm, b=500cm. This therefore gives us c=1581.14cm. converted back into metres, c=1.58 metres.

MS
Answered by Morgan S. Maths tutor

3249 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Looking at the diagram, work out the angle of a) x, b) y, and c) z


ABD is a triangle, C lies on BD. AD=BD=√2/2 and CD=√3/3. Find the EXACT area of ABC. (all measurements are in cm)


Solve the inequality x^2 + 5x -24 ≥ 0.


Find f^-1(x) for the following equation: f(x) = (12+x)/3


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning