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Solve the simultaneous equations: y-2x-4 = 0 (1) , 4x^2 +y^2 + 20x = 0 (2)

Re-arrange (1) : y = 2x + 4 Square both sides: y^2 = 4x^2 + 16 Substitute (1) into (2) and simplify: 2x^2 + 9x + 4 = 0 Factorise the equation: (2x+1)(x+4) = 0 Solve for x: x = -1/2 and x = -4 Substitute these x values in (1) to find corresponding y values for each x.

Answered by Giorgos A. • Maths tutor

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Solve the simultaneous equations: y-2x-4 = 0 (1) , 4x^2 +y^2 + 20x = 0 (2)

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