How would you solve a quadratic equation (e.g. x^2-8x+15=0)?

There are two ways to solve the equation. One is to simply factorise it and the other is to use the formula provided in the formula booklet. The second method is probably easier when there isn't a nice easy number, such as in this example. To do it, you should read the equation as ax^2+bx+c=0, substituting the values into the equation- and remember to do it for both plus and minus! To factorise, you will need put the equation in the form (x+z)(x+t)=0. To do this, you work out the factors both of one (as there is only 1 x^2) and 15 which will add up to -8 to get you your z and t values.

JG
Answered by Jane G. Maths tutor

2805 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

What actully is the derivative of a function? What does it represent?


There are 10 boys and 20 girls in a class. The mean mark for the class is 60, the mean mark for the girls is 54. Work out the mean mark for the boys.


Solve 5x – 2 > 3x + 11


Solve the following inequality: x^2 + x -12<0


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences