How would you solve a quadratic equation (e.g. x^2-8x+15=0)?

There are two ways to solve the equation. One is to simply factorise it and the other is to use the formula provided in the formula booklet. The second method is probably easier when there isn't a nice easy number, such as in this example. To do it, you should read the equation as ax^2+bx+c=0, substituting the values into the equation- and remember to do it for both plus and minus! To factorise, you will need put the equation in the form (x+z)(x+t)=0. To do this, you work out the factors both of one (as there is only 1 x^2) and 15 which will add up to -8 to get you your z and t values.

JG
Answered by Jane G. Maths tutor

2947 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

The first 4 terms of a different sequence are: 9, 13, 17, 21. Find an expression for the nth term of the sequence.


Solve the simultaneous equations: 2x+5y=25, x=y+2


Find the coordinates of the point of intersection of the lines 2x + 3y = 12 and y = 7 - 3x.


Solve x(x-1)-12=0


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning