f(x) = x^2 + 4x − 6 f(x) can be written in the form (x + m)^2 + n. Find the value of m and the value of n.

Because we know (x+m)^2 expanded will provide x^2+2mx+m^2 and we have the extra addition of a value named n we can strictly focus on ensuring the expansion yields x^2+4x and deal with the -6 value by using n. Thus, by putting m as 2 we get x^2+4x+4, and following through to achieve -6 instead of 4, we put n as -10, and so we get the desired answer.

MG
Answered by Majed G. Maths tutor

9670 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Expand the brackets: (3a+3)(a+4)


The perimeter of a right-angled triangle is 72 cm. The lengths of its sides are in the ratio 3 : 4 : 5 Work out the area of the triangle


Solve the simultaneous equations x^2 + y^2 = 9 and x+ y = 2. Give your answer to 2.d.p


How do I solve the simultaneous equations x-2y=1 and x^2-xy+y^2=1?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences