What is the area of triangle ABC where AB = 5 cm, BC = 12 cm and angle ABC = 50 degrees?

To find the area of a triangle where the length of the base and perpendicular heights are not known, use the sine rule to find the area. This is: Area = 0.5 x a x b x sin(angle between lengths a and b) Hence for the above numbers, area = 0.5 x 5 cm x 12 cm x sin(50 degrees) = 23 sq. cm (put numbers into calculator)

AS
Answered by Aminah S. Maths tutor

8330 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Answer quadratic equation in the simplest surd form/ exact from. 5-2x-x^2=0


Prove that 1/sin(2theta) - cos(2theta)/sin(2theta) = tan(theta)


expand and simplify (x+3)(x-7)


Solve the simultaneous equations to find x and y: 3y - x = 12 y + 2x = -3


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences