A baby in a bouncer bounces up and down with a period of 1.2s and amplitude of 90mm. Calculate the baby's maximum velocity.

Relevant equations: 1) frequency = 1/ time period; 2) v(max) = Amplitude*(2pifrequency)

First, we need to calculate the frequency of the baby's oscillation. That is, the number of times, per second, that the baby moves up, then down, and back to their original position. We do this by substituting the values into equation 1. Then, we use that value in equation 2 to find the speed at which the baby moves fastest - their maximum velocity. They will travel at this speed when moving through their original position when their acceleration is zero.

SH
Answered by Sam H. Physics tutor

4293 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

A sequence is defined by the recurrence relation u(n+1) = 1/3 u(n) + 10 with u(3) = 6 . Find the value of u(4) and the limit of the sequence.


What is electricity


A jug containing 0.250 kg of liquid is put into a refrigerator. Its temperature decreased from 20°C to 15°C. The amount of energy transferred from the liquid was 5,250 J. Calculate the specific heat capacity of the liquid.


Which are the forms of heat you know. Explain them briefly including an example


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning