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Differentiate y=ln(2x^2) with respect to x

Making a substitution for u = 2x^2 Now y = ln(u) dy/dx = du/dx * dy/du du/dx = 4x dy/du = 1/u dy/dx = 4x/u Then substitute 2x^2 back in as u The final answer is 4x/(2x^2) Which can be simplified by dividing through by 2 and x to get 2/x

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Differentiate y=ln(2x^2) with respect to x

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y=4x/(x^2+5)