Given that y=(4x-3)^3 x sin2x find dy/dx

To begin with it is important to identify which method of differentiation is required here, since there are two terms multiplied together you would initially choose the product rule, differentiating (4x-3)^3 and sin2x separately. To differentiate the first term simply multiply the power by the coefficient of x which product is then multiplied by the bracket and the power reduces by 1. To differentiate sin2x, the trig rules must be remembered, which will give 2sin2x. To get the full differential multiply the second differential by the first term and then add the first differential by the second term.

MO
Answered by Max O. Maths tutor

3256 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

What is the probability to obtain exactly 2 heads out of 3 tosses of a fair coin?


The line l1 has equation 4y - 3x = 10. Line l2 passes through points (5, -1) and (-1, 8). Determine whether the lines l1 and l2 are parallel, perpendicular or neither.


Differentiate x^cos(x) and find the derivative of cosec^-1(x)


Show how '2sin(x)+sec(x+ π/6)=0' can be expressed as √3sin(x)cos(x)+cos^2(x)=0.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning