Solve the equation (3x+2)/(x-1)+3=4

First we must think about the fraction on the left hand side - we have to multiply everything by x-1 in order to get rid of the fraction. This leaves us with 3x+2+3(x-1)=4(x-1). Then, we must expand the brackets, which gives us 3x+2+3x-3=4x-4. Now we will collect similar terms, i.e. collect the xs together and the constants together, to get 6x-1=4x-4. Bringing all the x terms onto the left hand side, and the constant terms onto the right hand side, we get 2x=-3. Finally, dividing through by 2 we are left with x=-3/2, the solution to the equation.

MS
Answered by Mary S. Maths tutor

4414 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations: 3x + 2y = 4 and 4x + 5y = 17


Solve the simultaneous equations '2X+Y=7' and '3X-Y=8'


How do you use Substitution to solve simultaneous equations?


A linear sequence starts: a+2b, a+6b, a+10b, ..., ... The 2nd term has a value of 8. The 5th term has a value of 44. Work out the values of a and b.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning