Show that Sec2A - Tan2A = (CosA-SinA)/(CosA+SinA)

Sec2A - Tan2A Definition of Sec and Tan = 1/Cos2A - Sin2A/Cos2A Combining Fractions = (1 - Sin2A) / (Cos2A) Apply Double Angle Formula = (1 - 2SinACosA) / (Cos2A - Sin2A) Make use of 1 = Cos2x + Sin2x and Difference of two squares = (Cos2A + Sin2A - 2SinACosA) / (CosA + SinA)(CosA - SinA) Factorise the numerator = (CosA - SinA)2 / (CosA + SinA)(CosA - SinA) Divide out by (CosA - SinA) = (CosA - SinA) / (CosA + SinA)

JC

Related Maths A Level answers

All answers ▸

Solve the simultaneous equations y = x^2 - 6x and 2y + x - 6 = 0


C and D are two events such that P(C) = 0.2, P(D) = 0.6 and P(C|D) = 0.3. Find P(D|C), P(C’ ∩ D’) & P(C’ ∩ D)


Express 4sin(x)+6cos(x) in terms of Rsin(x+a) where R and a are constants to be determined (a should be given in rad).


Find, using calculus, the x coordinate of the turning point of the curve y=e^(3x)*cos(4x) pi/4<x<pi/2 (Edexcel C3)