Show that Sec2A - Tan2A = (CosA-SinA)/(CosA+SinA)

Sec2A - Tan2A Definition of Sec and Tan = 1/Cos2A - Sin2A/Cos2A Combining Fractions = (1 - Sin2A) / (Cos2A) Apply Double Angle Formula = (1 - 2SinACosA) / (Cos2A - Sin2A) Make use of 1 = Cos2x + Sin2x and Difference of two squares = (Cos2A + Sin2A - 2SinACosA) / (CosA + SinA)(CosA - SinA) Factorise the numerator = (CosA - SinA)2 / (CosA + SinA)(CosA - SinA) Divide out by (CosA - SinA) = (CosA - SinA) / (CosA + SinA)

JC
Answered by James C. Maths tutor

34769 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Differentiate: y = 2 ^ x


Find dy/dx when y=(3x-1)^10


Let f(x)=x^3 - 2x^2 + 5. For which value(s) of x does f(x)=5?


Using mathematical induction, prove De Moivre's Theorem.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences