show that tan(x)/sec2(x) = (1/2)sin(2x)

tan(x)/sec2(x) Sec(x) = 1/cos(x), therefore 1/sec(x) = cos(x). also tan(x) = sin(x)/cos(x).using substitution, tan(x)/sec2(x) = (sin(x)/cos(x)) * cos2(x) = sin(x)cos(x). sin(x+y) = sin(x)cos(y) + cos(x)sin(y). since 2x = x+x, sin(2x) = 2sin(x)cos(x). therefore, sin(x)cos(x) = (1/2)sin(2x)

OO
Answered by Olaitan O. Maths tutor

4985 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

The curve C has equation 4x^2 – y^3 – 4xy + 2^y = 0 The point P with coordinates (–2, 4) lies on C . Find the exact value of dy/dx at the point P .


Given y = x(3x+ 5)^3. Find dy/dx.


Find the area under the curve y = (4x^3) + (9x^2) - 2x + 7 between x=0 and x=2


How do I differentiate y=(4+9x)^5 with respect to x?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning