Solve this simultaneous equation: 5x+6y=3 and 2x-3y=12.

Firstly, I will provide a mark scheme and then a full explanation underneath. 5x+6y=3. (1) 2x-3y=12. (2). (5x+6y=3)+(2(2x-3y=12)). (5x+6y=12)+ (4x-6y=24). 9x=27. x=3. Put x is (1) 5(3)+6y=3=15+6y=3. 6y=-12. y=-2. Check in (2). 2(3)-3(-2)=12. 12=12. Therefore x=3 and y=-2. 5x+6y=3. 2x-3y=12. Now a full explanation: Treat 5x+6y=3 as No. 1 equation. Treat 2x-3y=12 as No.2 equation. Therefore, 5x+6y=3 (1) and 2x-3y=12 (2). (There needs to be something equal about these two equations. TOP TIP: REMEMBER WHEN DOUBLING BOTH THINGS EITHER SIDE OF THE '=', IT STILL MEANS THE SAME THING :) YOU CAN PRETTY MUCH DO ANYTHING TO AN EQUATION AS LONG AS YOU DO THE SAME THING FOR EITHER SIDE OF THE '=' SIGN). In this case, an easy way to make the equation equal and able to manipulate would be to multiply (2) by 2. Therefore,  2(2x-3y)= 24. This equals 4x-6y=24. Now as the y's are equal you can 'simultaneously' solve them. Effectively, we need to get rid of the y's. Therefore add (5x+6y=3) and (4x-6y=24). This gives us 9x=27. (as 5+4 =9, 6-6=0 and 3+24=27.) Therefore, x=3. Now put x= back into one of the equation, for example in (1). This gives 5(3)+6y=3. Therefore 15+6y=3. (take 15 from both sides). 6y=3-15. . 6y=-12. (divide both sides by 6). y=-2. Therefore x=3. y=-2. Feel free to check your results using (2) to make sure your answers right. Therefore, 2(3)-3(-2)=12. This gives 6--6=12. 12=12. Therefore, we have got the right answer.

AM
Answered by Ashni M. Maths tutor

11704 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Edexcel, 2016, Foundation Maths GCSE: A running club has 50 members. 30 members take part in road races, 15 members take part in fell races, 12 members do not run in road or fell races. How many members run both fell and road races?


Solve the equation (2x+3)/(x-4)-(2x-8)/(2x+1)=1 and give the answer to 2 decimal places


Plot the graph for y = 4x - 3


Make r the subject of the formula x = (3r - 4)/5


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning