Consider a differential equation where dx/dt = -axt. Find an equation for x(t).

Starting from dx/dt = -axt.                                We treat dx and dt as infinitessimal factors of x and t, therefore fundemental mathematical operations still apply. Rearranging the equation to group x, dx and t, dt. 1/x dx = -at dt.                               Note: We could rearrange with a on the left handside but since we want to find an equation for x(t) it is convienent to seperate all constants.                             We now have the integral:           S 1/x dx = -a S t dt.                            ln x =-(1/2)at+ c .                       Where c is an integrating constant.                     x(t)=Aexp(-(1/2)at2).                    Define A = exp(c).

CL
Answered by Cal L. Maths tutor

4773 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Let y(x) be a function with derivative y'(x)=x^2-2 and y(0) =7. What is the value of y at x = 3?


Find the stationary points of the function f(x) = x^3+6x^2+2 and determine if they are local maximums or minimums.


∫2x(x+2)^(1/2) dx evaluated from 0->2


A curve has the equation 6x^(3/2) + 5y^2 = 2 (a) By differentiating implicitly, find dy/dx in terms of x and y. (b) Hence, find the gradient of the curve at the point (4, 3).


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning