A curve has the equation x^2+2y^2=3x, by differentiating implicitly find dy/dy in terms of x and y.
We shall differentiate each term in the equation with respect to x.
dy/dx (x2) = 2x
dy/dx (2y2) = 4y dy/dx
dy/dx (3x) = 3
So we now have the equation 2x + 4y dy/dx =3
We now have to rearrange to get in the form dy/dx
dy/dx= (3-2x)/4y
KP
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