The polynomial p(x) is given: p(x)=x^3+2x^2-5x-6, express p(x) as the product of three linear factors

p(x)=x3+2x2-5x-6

      =x(x2+2x-5)-6

      =x(x2+2x+1-6)-6 as we know (x+1)2=x2+2x+1,5 can be expressed 1-6

      =x[(x+1)2-6]-6

      =x(x+1)2-6x-6

      =x(x+1)2-6(x+1)

      =(x+1)[x(x+1)-6]

      =(x+1)(x2+x-6) here, -6 can be expressed as -2*3, and -2+3=1 

      =(x+1)(x+3)(x-2)

 

JB
Answered by Jingyi B. Maths tutor

13560 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

The equation of a line is y=e(^2x)-9 and the line has points at (0,a) and (b,0). Find the values of a and b.


a curve has an equation: y = x^2 - 2x - 24x^0.5 x>0 find dy/dx and d^2y/dx^2


The curve C is defined by x^3 – (4x^2 )y = 2y^3 – 3x – 2. Find the value of dy/dx at the point (3, 1).


What does differentiation actually do?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences